Skip to main content
Singapore Math 5B · Original independent course

Chapter 13 Review

Formative chapter review. Work independently, then reveal the feedback.

Original assessment

1 · MATH-5B-C13-REVIEW-Q01

A collection has 5 bronze and 7 silver badges. Give bronze:silver and silver:bronze in order.

Show worked answer (after attempting)
Answer: 5:7 and 7:5

Order follows the named category; swapping the order changes the comparison.

2 · MATH-5B-C13-REVIEW-Q02

A report writes silver:bronze = 5:7 for 5 bronze and 7 silver badges. Is that right?

Show worked answer (after attempting)
Answer: No; 7:5

The report reversed which quantity comes first.

3 · MATH-5B-C13-REVIEW-Q03

Scale the ratio 4:9 by a factor of 3, keeping it equivalent.

Show worked answer (after attempting)
Answer: 12:27

Multiply both terms by the same nonzero factor.

4 · MATH-5B-C13-REVIEW-Q04

Two cards read 4:9 and 12:27. Are they equivalent? Verify by cross-products.

Show worked answer (after attempting)
Answer: Yes

4×27 = 9×12.

5 · MATH-5B-C13-REVIEW-Q05

A:B = 6:7; A has 24 pieces. Find B and state the common multiplier.

Show worked answer (after attempting)
Answer: B=28

Unit scale t=4; multiply B parts 7 by 4.

6 · MATH-5B-C13-REVIEW-Q06

A:B = 6:7; B has 28 pieces. Find A using equal-sized ratio parts.

Show worked answer (after attempting)
Answer: A=24

Divide B by 7 to get 4 per part; multiply 6 parts.

7 · MATH-5B-C13-REVIEW-Q07

If A:B=8:9 and B:C=9:9, form A:B:C.

Show worked answer (after attempting)
Answer: 8:9:9

B already uses the same number of parts in both ratios.

8 · MATH-5B-C13-REVIEW-Q08

A:B=8:9 and B:C=18:18. Find A:B:C in the smallest matching integer parts.

Show worked answer (after attempting)
Answer: 8:9:9

Divide the second pair by 2; B then matches.

9 · MATH-5B-C13-REVIEW-Q09

A team splits 54 tokens in the ratio 7:11. Find each share and verify their sum.

Show worked answer (after attempting)
Answer: 21 and 33

Total parts 18; each part = 54 ÷ 18 = 3.

10 · MATH-5B-C13-REVIEW-Q10

Two groups share tokens in ratio 7:11. The first receives 21. How many must the second receive?

Show worked answer (after attempting)
Answer: 33

21 ÷ 7 = 3 per part; second 33.