A tap adds 2.6 L/min. Find water after 4 minutes.
Word Problems
Watch for: Confusing a changing total with a fixed per-unit rate.. Explain what the quantities mean before calculating.
Opening task
Prerequisite check
At 3 L/min, how much water arrives in 5 minutes?
Show worked answer (after attempting)
Rate × time = 3 × 5 = 15 L.
Understand the idea
Interpret rates in varied practical contexts, explaining both arithmetic and unit meaning. The essential earlier idea is: Chapter 14 L01–L03, ratios, whole/decimal operations.. The model below will always use the actual quantities from the worked problem. Check confusing a changing total with a fixed per-unit rate when you explain your answer.
Three worked examples
Worked example 1 · MATH-5B-C14-L04-Q01
A tap adds 2.5 L/min. Find water after 4 minutes.
Solution: 10 L
Use the constant rate only within the described situation: 2.5 L/min × 4 = 10 L.
Worked example 2 · MATH-5B-C14-L04-Q02
Each identical bag uses 3.2 kg of grain. How much for 5 bags?
Solution: 16 kg
Use the constant rate only within the described situation: 3.2 kg/bag × 5 = 16 kg.
Worked example 3 · MATH-5B-C14-L04-Q03
Travel is 1.8 km/h. What is distance in 6 hours?
Solution: 10.8 km
Use the constant rate only within the described situation: 1.8 km/h × 6 = 10.8 km.
Check understanding
A tap adds 2.6 L/min. Find water after 4 minutes.
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.6 L/min × 4 = 10.4 L.
Each identical bag uses 3.3 kg of grain. How much for 5 bags?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3.3 kg/bag × 5 = 16.5 kg.
Travel is 1.9 km/h. What is distance in 6 hours?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 1.9 km/h × 6 = 11.4 km.
Guided practice
A tap adds 2.7 L/min. Find water after 4 minutes.
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.7 L/min × 4 = 10.8 L.
Each identical bag uses 3.4 kg of grain. How much for 5 bags?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3.4 kg/bag × 5 = 17 kg.
Travel is 2 km/h. What is distance in 6 hours?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2 km/h × 6 = 12 km.
A tap adds 2.8 L/min. Find water after 4 minutes.
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.8 L/min × 4 = 11.2 L.
Independent practice
Each identical bag uses 3.5 kg of grain. How much for 5 bags?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3.5 kg/bag × 5 = 17.5 kg.
Travel is 2.1 km/h. What is distance in 6 hours?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.1 km/h × 6 = 12.6 km.
A tap adds 2.9 L/min. Find water after 4 minutes.
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.9 L/min × 4 = 11.6 L.
Each identical bag uses 3.6 kg of grain. How much for 5 bags?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3.6 kg/bag × 5 = 18 kg.
Travel is 2.2 km/h. What is distance in 6 hours?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.2 km/h × 6 = 13.2 km.
A tap adds 3 L/min. Find water after 4 minutes.
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3 L/min × 4 = 12 L.
Each identical bag uses 3.7 kg of grain. How much for 5 bags?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3.7 kg/bag × 5 = 18.5 kg.
Travel is 2.3 km/h. What is distance in 6 hours?
Show worked answer (after attempting)
Use the constant rate only within the described situation: 2.3 km/h × 6 = 13.8 km.
Challenge and error analysis
The assigned question is: “Each identical bag uses 4 kg of grain. How much for 5 bags?” A learner wrote: “I treated the constant rate involving 4 as the whole amount rather than amount per unit, and wrote 20.1 kg.” Identify a concrete invalid step or assumption. Work out the correct result and explain why it is valid.
Show worked answer (after attempting)
The attempted reasoning or reported result does not satisfy the specified operation, units or geometric conditions. Correct mathematical result: 20 kg. Recompute from the given data: Use the constant rate only within the described situation: 4 kg/bag × 5 = 20 kg.
The assigned question is: “Travel is 2.6 km/h. What is distance in 6 hours?” A learner wrote: “I treated the constant rate involving 2.6 as the whole amount rather than amount per unit, and wrote 16.6 km.” Identify a concrete invalid step or assumption. Work out the correct result and explain why it is valid.
Show worked answer (after attempting)
The attempted reasoning or reported result does not satisfy the specified operation, units or geometric conditions. Correct mathematical result: 15.6 km. Recompute from the given data: Use the constant rate only within the described situation: 2.6 km/h × 6 = 15.6 km.
Exit check
A tap adds 3.1 L/min. Find water after 4 minutes.
Show worked answer (after attempting)
Use the constant rate only within the described situation: 3.1 L/min × 4 = 12.4 L.